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![]() When checking for integer overflow, you may often write tests like p + i < p. This works fine if p and i are unsigned integers, since any overflow in the addition will cause the value to simply "wrap around." However, using this pattern when p is a pointer is problematic because pointer overflow has undefined behavior according to the C and C++ standards. If the addition overflows and has an undefined result, the comparison will likewise be undefined; it may produce an unintended result, or may be deleted entirely by an optimizing compiler. |
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aot | ||
common | ||
compilation | ||
doc | ||
fast-jit | ||
include | ||
interpreter | ||
libraries | ||
README.md |